The main weakness it has is from a nosey flatmate, spouse, or child in the house.
I disagree. Using this book will always lead to shorter passwords that are easier to type. That’s the main weakness imo.
Or in other words: it really depends what the user fills it with. It should be accompanied by a little machine that spits out random passwords, I’m thinking a rubics-cube-shaped bling pendant at the end of the bookmark band.
Which you then have to type out every time. Laziness wins: they will be shorter.
The assumption is that the product is for non-savvy users. They might not even understand what you wrote up there.
Autocorrect can help here, but dictionary words are easily brute-forced guessed. And - more importantly - that hypothetical user would have to come up with that idea in the first place. But people who come up with such ideas usually already use password managers anyhow.
I’m imagining a different character on each face of each cubelet, which you would throughly scramble each time for a one-in-whatever-gagillion string? Am I getting that right?
I disagree. Using this book will always lead to shorter passwords that are easier to type. That’s the main weakness imo.
Or in other words: it really depends what the user fills it with. It should be accompanied by a little machine that spits out random passwords, I’m thinking a rubics-cube-shaped bling pendant at the end of the bookmark band.
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Which you then have to type out every time. Laziness wins: they will be shorter.
The assumption is that the product is for non-savvy users. They might not even understand what you wrote up there.
Autocorrect can help here, but dictionary words are easily
brute-forcedguessed. And - more importantly - that hypothetical user would have to come up with that idea in the first place. But people who come up with such ideas usually already use password managers anyhow.deleted by creator
Using special terms wrongly doesn’t mean I’m clueless, cryptobro.
Correct horse battery staple
I’m imagining a different character on each face of each cubelet, which you would throughly scramble each time for a one-in-whatever-gagillion string? Am I getting that right?